2x-3y = 12
3 x +4y = 1![]()
3 x +4y = 1
"Persamaan 1"
2x-3y = 12
2x = 12 + 3y
x = (12+3y)/2
"Persamaan 2"
3[(12+3y)/2] + 4y = 1
3[6+(3/2)y] + 4y = 1
18 + (9/2)y + 4y = 1
18 + (9/2 + 4)y = 1
(17/2)y = -17
y = -17 × (2/17)
y = -2
Setelah nilai y diketahui, substitusikan ke persamaan tadi
2x - 3(-2) = 12
2x - (-6) = 12
2x + 6 = 12
2x = 6
x = 3
So
x = 3
y = -2
[answer.2.content]
